Q142 / 200 · NEET 2023 (Manipur) · Physics

The ground state energy of hydrogen atom is $-13.6 \mathrm{eV}$. The energy needed to ionize hydrogen atom from its second excited state will be

  • Correct answer
    A
    $1.51 \mathrm{eV}$
  • B
    $3.4 \mathrm{eV}$
  • C
    $13.6 \mathrm{eV}$
  • D
    $6.8 \mathrm{eV}$

Solution

We know that total energy of electron in hydrogen atom is given by $E_\eta=\frac{-13.6}{n^2}$ Also, total energy of electron in second excited state $=\frac{-13.6}{(3)^2}=-1.51 \mathrm{eV}$ $\Rightarrow$ lonization energy or energy required to ionize hydrogen atom from its second excited state $=1.51 \mathrm{eV}$

Hence, the correct answer is option: 'A'.

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