Q124 / 150 · MHT CET 2025 (22 Apr Shift 1) · Physics

The graph shows the variation of voltage (v) across the plates of two parallel plate capacitors A and B versus increase of charge Q stored in them. Then Figure

  • A
    capacity of both capacitors is same.
  • Correct answer
    B
    capacity of $A$ is higher than $B$.
  • C
    capacity of $B$ is higher than $A$.
  • D
    capacity of both is zero.

Solution

The relationship between charge and voltage for a capacitor is given by $Q = CV$, which rearranges to $V = \frac{1}{C}Q$.

Comparing this with the standard linear form $y = mx$, the slope of the V-Q graph equals $\frac{1}{C}$.

Since capacitor B's graph has a steeper slope than A's, we have $\frac{1}{C_B} > \frac{1}{C_A}$, and thus $C_B < C_A$.

Therefore, capacitor B has smaller capacitance than capacitor A.

Final answer: $\boxed{B}$

Hence, the correct answer is option: 'B'.

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