Q30 / 90 · JEE Main 2023 (30 Jan Shift 2) · Chemistry

The graph of logxmvs log p for an adsorption process is a straight line inclined at an angle of 45° with intercept equal to 0.6020. The mass of gas adsorbed per unit mass of adsorbent at the pressure of 0.4 atm is _____×10-1 (Nearest integer)

Given : log2=0.3010

Correct answer: 16

Solution

The graphical representation of logarithmic form of Freundilich adsorption isotherm is as follows,

Figure

The logarithmic form of Freundilich adsorption isotherm is

logxm=logk+1nlogP

1n=tan45°=1

logk=0.6020=log4

⇒K=4

∴  xm=K·P1/n

xm=40.4=1.6

xm=1.6=16×10-1

Hence, the correct answer is 16.

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