Q63 / 160 · AP EAMCET 2025 (23 MAY SHIFT 2) · Mathematics

The general solution satisfying both the equations $\sin x=-\frac{3}{5}$ and $\cos x=-\frac{4}{5}$ is

  • Correct answer
    A
    $\mathrm{x}=(2 \mathrm{n}+1) \pi+\operatorname{Tan}^{-1}\left(\frac{3}{4}\right), \mathrm{n} \in \mathrm{Z}$
  • B
    $\mathrm{x}=2 \mathrm{n} \pi+\operatorname{Tan}^{-1}\left(\frac{3}{4}\right), \mathrm{n} \in \mathrm{Z}$
  • C
    $\mathrm{x}=\mathrm{n} \pi+\operatorname{Tan}^{-1}\left(\frac{3}{4}\right), \mathrm{n} \in \mathrm{Z}$
  • D
    $\mathrm{x}=\mathrm{n} \pi \pm \operatorname{Tan}^{-1}\left(\frac{3}{4}\right), \mathrm{n} \in \mathrm{Z}$

Hence, the correct answer is option: 'A'.

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