Q93 / 150 · MHT CET 2016 · Mathematics

The general solution of the equation $\tan^{2} x = 1$ is

A
$n π + \frac{π}{4}$
B
$n π - \frac{π}{4}$
Correct answer
C
$n π \pm \frac{π}{4}$
D
$2 n π \pm \frac{π}{4}$

Solution

\tan^{2} x = 1

∴ \tan x = \pm 1

= x = n π \pm \frac{π}{4}

Hence, the correct answer is option: 'C'.

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