Q29 / 90 · JEE Main 2024 (05 Apr Shift 2) · Chemistry

The fusion of chromite ore with sodium carbonate in the presence of air leads to the formation of products \(\mathrm{A}\) and \(\mathrm{B}\) along with the evolution of \(\mathrm{CO}_2\). The sum of spin-only magnetic moment values of \(A\) and \(B\) is ______ B.M. (Nearest integer) [Given atomic number : \(\mathrm{C}: 6, \mathrm{Na}: 11, \mathrm{O}: 8, \mathrm{Fe}: 26, \mathrm{Cr}: 24\)]

Correct answer: 6

Solution

Figure
Spin only magnetic moment For $\mathrm{Na}_2 \mathrm{CrO}_4 \quad \mu_{\mathrm{B}}=0$ For $\mathrm{Fe}_2 \mathrm{O}_3 \quad \mu_{\mathrm{B}}=5.9$ sum $=5.9$

Hence, the correct answer is 6.

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