Q70 / 150 · MHT CET 2022 (08 Aug Shift 1) · Mathematics

The function, $f(x)=x \sqrt{1-x}$, where $x \in(0,1)$, has local maximum at $x=$

  • A
    $\frac{1}{3}$
  • B
    $\frac{1}{4}$
  • Correct answer
    C
    $\frac{2}{3}$
  • D
    $\frac{3}{4}$

Solution

$\begin{aligned} & f(x)=x \sqrt{1-x} \\ & \Rightarrow f^{\prime}(x)=1 \sqrt{1-x}+\frac{x}{2 \sqrt{1-x}} x(-1)=\frac{2-3 x}{2 \sqrt{1-x}} \end{aligned}$ sign scheme of $f^{\prime}(x)$ Figure
Hence, local maxima at $x=\frac{2}{3}$

Hence, the correct answer is option: 'C'.

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