Q88 / 200 · WBJEE 2014 · Mathematics
The function $f(x)=a \sin |x|+b e^{| x \mid} \quad$ is differentiable at $x=0$ when
- A$3 a+b=0$
- B$3 a-b=0$
- Correct answerC$a+b=0$
- D$a-b=0$
Solution
Given, $f(x)=a \sin |x|+b e^{|x|}$
We know that $\sin |x|$ and $e^{|x|}$ is not
differentiable at $x=0$.
Therefore, for $f(x)$ to differentiable at $x=0$, we
must have $a=b=0$.
$\therefore$
$$
a+b=0
$$
Hence, the correct answer is option: 'C'.