Q69 / 125 · BITSAT 2015 · Mathematics

The function $\mathrm{f}(\mathrm{x})=\frac{\mathrm{x}}{2}+\frac{2}{\mathrm{x}}$ has a local minimum at

  • A
    $x=2$
  • B
    $x=-2$
  • C
    $x=0$
  • Correct answer
    D
    $x=1$

Solution

$\frac{x}{2}+\frac{2}{x}$ is of the form $x+\frac{1}{x} \geq 2$ and equality holds for $x=1$

Hence, the correct answer is option: 'D'.

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