Q224 / 270 · NDA 2017 (Phase 1) · Mathematics
The function $f: \mathrm{X} \rightarrow \mathrm{Y}$ defined by $f(\mathrm{x})=\cos \mathrm{x}$, where $\mathrm{x} \in \mathrm{X}$, is one-one and onto if X and Y are respectively equal to
- Correct answerA$[0, \pi]$ and $[-1,1]$
- B$\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \operatorname{and}[-1,1]$
- C$[0, \pi]$ and $(-1,1)$
- D$[0, \pi]$ and $[0,1]$
Solution
Observe the cosx graph in the figure.

It is clear that, function is one - one and onto when x and y are $[0, \pi]$ and $[-1,1]$

It is clear that, function is one - one and onto when x and y are $[0, \pi]$ and $[-1,1]$
Hence, the correct answer is option: 'A'.