Q224 / 270 · NDA 2017 (Phase 1) · Mathematics

The function $f: \mathrm{X} \rightarrow \mathrm{Y}$ defined by $f(\mathrm{x})=\cos \mathrm{x}$, where $\mathrm{x} \in \mathrm{X}$, is one-one and onto if X and Y are respectively equal to

  • Correct answer
    A
    $[0, \pi]$ and $[-1,1]$
  • B
    $\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \operatorname{and}[-1,1]$
  • C
    $[0, \pi]$ and $(-1,1)$
  • D
    $[0, \pi]$ and $[0,1]$

Solution

Observe the cosx graph in the figure. Figure
It is clear that, function is one - one and onto when x and y are $[0, \pi]$ and $[-1,1]$

Hence, the correct answer is option: 'A'.

Relevant Questions