The formation of O_2^+ [PtF_6 ]^- is basis for the formation of xenon fluorides. This is because

Correct answer: (C) O_2 and Xe have comparable ionisation energies. The formation of O_2^+ [PtF_6 ]^- is the basis for the formation of xenon fluorides because O_2 and Xe have - comparable ionisation energies.

Q19 / 180 · COMEDK 2018 · Chemistry

The formation of $\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}$is basis for the formation of xenon fluorides. This is because

A
$\mathrm{O}_{2}$ and Xe have comparable sizes
B
Both $\mathrm{O}_{2}$ and $\mathrm{Xe}$ are gases
Correct answer
C
$\mathrm{O}_{2}$ and Xe have comparable ionisation energies
D
$\mathrm{O}_{2}$ and Xe have comparable electronegativities

Solution

The formation of $\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}$is the basis for the formation of xenon fluorides because $\mathrm{O}_{2}$ and $\mathrm{Xe}$ have - comparable ionisation energies.

Hence, the correct answer is option: 'C'.

The formation of $\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}$is basis for the formation of xenon fluorides. This is because

Solution

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