The formal charges of $\mathrm{N}_{(1)}, \mathrm{N}_{(2)}$ and $\mathrm{O}$ atoms in
are respectively

• A

  +1,-1,0
• Correct answer
  B

  -1,+1,0
• C

  +1,+1,0
• D

  -1,-1,0

Solution

$\begin{aligned} & \text { Formal charge }=\left[\begin{array}{l}\text { Total number of valence } \\ \text { electrons in the free atom }\end{array}\right] \\ & -\left[\begin{array}{l}\text { Total number of } \\ \text { non-bonding (lone } \\ \text { pair)electrons }\end{array}\right]-\frac{1}{2}\left[\begin{array}{l}\text { Total number of } \\ \text { bonding (shared) } \\ \text { electrons }\end{array}\right]\end{aligned}$ In
structure the formal charge on.... the end $\mathrm{N}$ atom marked 1 , $\begin{aligned} & =5-4-\frac{1}{2}(4) \\ & =5-4-2=-1 \end{aligned}$ the central $\mathrm{N}$ atom marked 2 , $\begin{aligned} & =5-0-\frac{1}{2}(8) \\ & =5-4=+1 \end{aligned}$ the end $\mathrm{O}$ atom, $\begin{aligned} & =6-4-\frac{1}{2}(4) \\ & =6-6=0 \end{aligned}$

Hence, the correct answer is option: 'B'.