Q134 / 160 · AP EAMCET 2025 (22 MAY SHIFT 1) · Physics

The force required to stretch a steel wire of area of cross-section $1 \mathrm{~mm}^2$ to double its length is (Young's modulus of steel $=2 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$ )

  • A
    $2 \times 10^3 \mathrm{~N}$
  • Correct answer
    B
    $2 \times 10^5 \mathrm{~N}$
  • C
    $2 \times 10^2 \mathrm{~N}$
  • D
    $2 \times 10^4 \mathrm{~N}$

Hence, the correct answer is option: 'B'.

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