Q134 / 160 · AP EAMCET 2025 (22 MAY SHIFT 1) · Physics
The force required to stretch a steel wire of area of cross-section $1 \mathrm{~mm}^2$ to double its length is
(Young's modulus of steel $=2 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$ )
- A$2 \times 10^3 \mathrm{~N}$
- Correct answerB$2 \times 10^5 \mathrm{~N}$
- C$2 \times 10^2 \mathrm{~N}$
- D$2 \times 10^4 \mathrm{~N}$
Hence, the correct answer is option: 'B'.