Q125 / 160 · AP EAMCET 2023 (18 May Shift 2) · Physics

The force required to stop a body of mass $10 \mathrm{~kg}$ moving along a straight line path with a velocity of $10 \mathrm{~ms}^{-1}$ in a time of $10 \mathrm{~s}$ is

  • Correct answer
    A
    $10 \mathrm{~N}$
  • B
    $1000 \mathrm{~N}$
  • C
    $100 \mathrm{~N}$
  • D
    $1 \mathrm{~N}$

Solution

Mass, $\mathrm{m}=10 \mathrm{~kg}$ Initial velocity, $u=10 \mathrm{~m} / \mathrm{s}$ Time, $\mathrm{t}=10 \mathrm{sec}$ final velocity, $\mathrm{V}=0$ using Newton's IInd law $$ \begin{aligned} & F=m a=m\left(\frac{V-u}{t}\right) \\ & =\frac{10 \times 10}{10}=10 \\ & F=10 N \end{aligned} $$

Hence, the correct answer is option: 'A'.

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