Q170 / 170 · Manipal (MET) 2020 · Physics

The force per unit length between two parallel current carrying straight conductors separated by $2 d$ is given by the formula

  • Correct answer
    A
    $\frac{\mu_0}{4 \pi} \frac{i_1 i_2}{d}$
  • B
    $\frac{\mu_0}{4 \pi} \frac{i_1 i_2}{2 d}$
  • C
    $\frac{\mu_0}{\pi} \frac{i_1 i_2}{2 d}$
  • D
    None of these

Solution

Force per unit length between the two parallel current carrying wires Figure
$\frac{F}{L}=\frac{\mu_0}{2 \pi r} i_1 i_2$ $=\frac{\mu_0}{2 \pi(2 d)} i_1 i_2=\frac{\mu_0 i_1 i_2}{4 \pi d} \quad[\because r=2 d]$

Hence, the correct answer is option: 'A'.

More Magnetic Effects of Current Questions