Q8 / 160 · TS EAMCET 2021 (06 Aug Shift 1) · Chemistry

The following graph indicates the system containing 1 mole of gas involving various steps. When it moves from $z$ to $x$, the type of undergoing process is Figure

  • A
    cyclic
  • B
    isothermal
  • C
    isochoric
  • Correct answer
    D
    isobaric

Solution

At $x \Rightarrow T_1=300 \mathrm{~K}, V_1=20 \mathrm{~L}$, pressure $=p_1$ At, $z \Rightarrow T_2=600 \mathrm{~K}, V_2=40 \mathrm{~L}$, pressure $=$ ? According to universal gas law $\begin{aligned} p V & =n R T \\ p V / T & =n R \quad(n R=\text { constant }) \\ \text { Then, } \quad p_1 V_1 / T_1 & =p_2 V_2 / T_2 \\ \frac{p_1 \times 20}{300} & =\frac{p_2 \times 40}{600} \\ p_1 & =p_2 \\ \Rightarrow \quad \text { i.e. process is isobaric. } & \end{aligned}$

Hence, the correct answer is option: 'D'.

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