The explosive in a Hydrogen bomb is a mixture of ${}_1\mathrm{H}^2,{}_1\mathrm{H}^3$ and ${}_3\mathrm{Li}^6$ in some condensed form. The chain reaction is given by ${}_3\mathrm{Li}^6+{}_0\mathrm{n}^1\to {}_2\mathrm{He}^4+{}_1\mathrm{H}^3$;  ${}_1\mathrm{H}^2+{}_1\mathrm{H}^3\to {}_2\mathrm{He}^4+{}_0\mathrm{n}^1$

During the explosion the energy released is approximately [Given : $M\left(\mathrm{Li}\right)=6.01690 \mathrm{amu}\mathit{,}\mathit{ }M\left({}_1\mathrm{H}^2\right)=2.01471 \mathrm{amu}, M\left({}_2\mathrm{He}^4\right)=4.00388 \mathrm{amu}$ and $1 \mathrm{amu}=931.5 \mathrm{MeV}$]

• A

  $28.12\mathrm{MeV}$
• B

  $12.64\mathrm{MeV}$
• C

  $16.48\mathrm{MeV}$
• Correct answer
  D

  $22.22\mathrm{MeV}$

Hence, the correct answer is option: 'D'.