The escape velocity is $11.2 \mathrm{~km} / \mathrm{s}$. If a body is to be projected in a direction making an angle $60^{\circ}$ to the vertical, then the escape velocity is

• A

  $11.2 \times \sqrt{2} \mathrm{~km} / \mathrm{s}$
• B

  $\frac{11.2}{\sqrt{2}} \mathrm{~km} / \mathrm{s}$
• C

  $11.2 \sqrt{3} \mathrm{~km} / \mathrm{s}$
• Correct answer
  D

  $11.2 \mathrm{~km} / \mathrm{s}$

Hence, the correct answer is option: 'D'.