The equivalent resistance between $A$ and $C$ of the given circuit, is

• A

  $8 \Omega$
• B

  $\frac{32}{14} \Omega$
• C

  $\frac{4}{3} \Omega$
• Correct answer
  D

  $\frac{8}{3} \Omega$.

Solution

The given circuit is a balanced Wheatstone bridge circuit. So, the resistance $7 \Omega$ may be regulated. Therefore, we have the equivalent circuit as,
$\therefore$ The quivalent resistance between $A$ and $B$ is $R=\frac{4 \times 8}{4+8}=\frac{32}{12}=\frac{8}{3} \Omega$

Hence, the correct answer is option: 'D'.