Q172 / 180 · KCET 2019 · Physics

The equivalent capacitance between \( A \) and \( B \) is,

A
\( 150 \mathrm{pF} \)
B
\( 50 \mathrm{pF} \)
C
\( 300 \mathrm{pF} \)
Correct answer
D
\( \frac{100}{3} \mathrm{pF} \)

Solution

(D)
\( C_{A B}=(50|| 50) \) series \( 50=\frac{100 \times 50}{100+50}=\frac{100}{3} p F \)

Hence, the correct answer is option: 'D'.

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