The equilibrium constant $\mathrm{K}_{\mathrm{c}}$ of the reaction $2 \mathrm{~A} \rightleftharpoons \mathrm{B}+\mathrm{C}$ is $0.5$ at $25^{\circ} \mathrm{C}$ and $\mathrm{i} \mathrm{atm}$. The reaction will proceed in the backward direction when concentrations [A], [B] and [C] are respectively :

• Correct answer
  A

  $10^{-3}, 10^{-2}$ and $10^{-2} \mathrm{M}$
• B

  $10^{-1}, 10^{-2}$ and $10^{-2} \mathrm{M}$
• C

  $10^{-2}, 10^{-2}$ and $10^{-3} \mathrm{M}$
• D

  $10^{-2}, 10^{-3}$ and $10^{-3} \mathrm{M}$

Hence, the correct answer is option: 'A'.