Q13 / 160 · TS EAMCET 2021 (05 Aug Shift 2) · Chemistry

The equilibrium constant for the reaction is $P_{4} (s) + 50_{2} (g) ⇌ P_{4} 0_{10} (s)$

A
$K_{c} = \sqrt{5 O_{2}}$
B
$K_{c} = [P_{4} O_{10}] / [P_{4}] {[O_{2}]}^{5}$
C
$K_{c} = {[O_{2}]}^{5}$
Correct answer
D
$K_{c} = \frac{1}{{[O_{2}]}^{5}}$

Solution

According to the question-
$P_{4} (s) + 5 O_{2} (g) \Leftrightarrow P_{4} O_{10} (s) Kc = \frac{[P_{4} O_{10} (s)]}{[P_{4} (s)] {[O_{2} (g)]}^{5}} [P_{4} (s)] = [P_{4} O_{10} (s)] = Constant Kc = {[O_{2} (g)]}^{5}$

Hence, the correct answer is option: 'D'.

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The equilibrium constant for the reaction is P4s+502g⇌P4010s

Solution

Relevant Questions

The equilibrium constant for the reaction is $P_{4} (s) + 50_{2} (g) ⇌ P_{4} 0_{10} (s)$