Q21 / 90 · JEE Main 2021 (27 Jul Shift 2) · Chemistry

The equilibrium constant for the reaction $A (s) ⇌ M (s) + \frac{1}{2} O_{2} (g)$ is $K_{p} = 4 .$ At equilibrium, the partial pressure of $O_{2}$ is _____ atm. (Round off to the nearest integer)

Correct answer: 16

Solution

$K_{p} = P_{O_{2}}^{1 / 2} = 4$

$∴ P_{O_{2}} = 16 atm$

Hence, the correct answer is 16.

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