The equations for the displacements of two particles in simple harmonic motion are $y_1=0.1 \sin \left(100 \pi t+\frac{\pi}{3}\right)$ and $y_2=0.1 \cos \pi t$ respectively. The phase difference between the velocities of the two particles at a time $t=0$ is

• A

  $\frac{\pi}{4}$
• B

  $\frac{\pi}{2}$
• Correct answer
  C

  $\frac{\pi}{6}$
• D

  $\frac{\pi}{3}$

Hence, the correct answer is option: 'C'.