Q93 / 160 · AP EAMCET 2020 (21 Sep Shift 2) · Mathematics

The equation of the tangent to the parabola \(y^2=12 x\) at \((3,-6)\) is

A
\(x-y+9=0\)
Correct answer
B
\(x+y+3=0\)
C
\(x+y-3=0\)
D
\(x=3\)

Solution

The equation of tangent to the parabola \(y^2=12 x\) at \((3,-6)\) is \(\begin{array}{llll} y(-6) =6(x+3) \\ \Rightarrow x+y+3 =0 \end{array}\) Hence, option (b) is correct.

Hence, the correct answer is option: 'B'.

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