Q106 / 160 · AP EAMCET 2024 (21 May Shift 2) · Mathematics
The equation of the tangent to the curve $y=x^3-2 x+7$ at the point $(1,6)$ is
- Correct answerA$y=x+5$
- B$2 x+y=8$
- C$x+y=7$
- D$x+2 y=13$
Solution
$y=x^3-2 x+7 \Rightarrow \frac{d y}{d x}=3 x^2-\left.2 \Rightarrow \frac{d y}{d x}\right|_{x=1}=1$
Equation of tangent is
$\frac{y-6}{x-1}=1 \Rightarrow x-y+5=0 \Rightarrow y=x+5$
$\frac{y-6}{x-1}=1 \Rightarrow x-y+5=0 \Rightarrow y=x+5$
Hence, the correct answer is option: 'A'.