Q26 / 107 · NTA Abhyas (JEE Main) 2020 · Physics · Oscillations

The equation of the resultant motion of the number of simple harmonic motions is Ec(1+Ksin⁡ω2t)sinω1t. The number of simple harmonic components is/are

  • A
    1
  • B
    2
  • Correct answer
    C
    3
  • D
    4

Solution

Y=Ec(1+Ksin⁡ω2t)sin ω1t

Y=Ecsin⁡ω2t+Ec ksin⁡ω2sin⁡ω1t

Y=Ecsin⁡ω1t+EcK2cos⁡ω2+ω1tEcK2ω2-ω1t
Thus there are three simple harmonic waves of frequency ω1, ω1+ω2 and ω1-ω2

Hence, the correct answer is option: 'C'.

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