Q95 / 150 · MHT CET 2019 (02 May Shift 1) · Mathematics

The equation of the plane passing through the point -1,2,1 and perpendicular to the line joining the points -3,1,2 and 2,3,4 is ________

  • Correct answer
    A
    r-.5i^+2j^+2k^=1
  • B
    r-.5i^+2j^+2k^=-1
  • C
    r-.5i^-2j^+2k^=-5
  • D
    r-.5i^-2j^-2k^=1

Solution

Since, direction ratio of normal
Are 2--3,3-1,4-2
= 5,2,2
Then, equation of plane is 5x+1+2y-2+2z-1=0
=5x+2y+2z-1=0
=r.¯5i+2j+2k=1
Or Equation of plane passing through
a¯=-i+2j-k and the position vector of normal n¯=5i+2j+2k
is r¯-a¯.n¯=0,r.¯5i+2j+2k=1

Hence, the correct answer is option: 'A'.

Relevant Questions