Q99 / 180 · KCET 2025 · Mathematics

The equation of the line through the point $(0,1,2)$ and perpendicular to the line $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}$ is

  • A
    $\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{-3}$
  • Correct answer
    B
    $\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}$
  • C
    $\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{3}$
  • D
    $\frac{x}{3}=\frac{y-1}{-4}=\frac{z-2}{3}$

Solution

$\mathrm{a}_1 \mathrm{a}_2+\mathrm{b}_1 \mathrm{~b}_2+\mathrm{c}_1 \mathrm{c}_2=0$

Hence, the correct answer is option: 'B'.

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