Q99 / 180 · KCET 2025 · Mathematics
The equation of the line through the point $(0,1,2)$ and perpendicular to the line $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}$ is
- A$\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{-3}$
- Correct answerB$\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}$
- C$\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{3}$
- D$\frac{x}{3}=\frac{y-1}{-4}=\frac{z-2}{3}$
Solution
$\mathrm{a}_1 \mathrm{a}_2+\mathrm{b}_1 \mathrm{~b}_2+\mathrm{c}_1 \mathrm{c}_2=0$
Hence, the correct answer is option: 'B'.