Q73 / 150 · MHT CET 2010 · Mathematics

The equation of the curve whose vertex is $(0,0)$ and length of latusrectum is $\frac{16}{3}$, is

A
$8 x^{2}+3 y^{2}=72$
B
$16 y^{2}=3 x$
Correct answer
C
$3 y^{2}=16 x$
D
$3 x^{2}+16 y^{2}=48$

Solution

For the curve $3 y^{2}=16 x$, the length of latusrectum is $\frac{16}{3}$

Hence, the correct answer is option: 'C'.

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