Q67 / 100 · BITSAT 2023 (Memory Based Paper 2) · Mathematics
The equation of the circle with centre $(0,2)$ and radius 2 is $x^2+y^2-m y=0$. The value of $m$ is
- A
1 - B
2 - Correct answerC
4 - D
3
Solution
Here $h=0, k=2$ and $r=2$. Therefore, the required equation of the circle is :
$(x-0)^2+(y-2)^2=(2)^2$
or $x^2+y^2-4 y+4=4$ or $x^2+y^2-4 y=0$
$(x-0)^2+(y-2)^2=(2)^2$
or $x^2+y^2-4 y+4=4$ or $x^2+y^2-4 y=0$
Hence, the correct answer is option: 'C'.