Q205 / 270 · NDA 2017 (Phase 2) · Mathematics

The equation of a straight line which cuts off an intercept of 5 units on negative direction of $y$-axis and makes an angle $120^{\circ}$ with positive direction of x -axis is

  • Correct answer
    A
    $\mathrm{y}+\sqrt{3} \mathrm{x}+5=0$
  • B
    $y-\sqrt{3} x+5=0$
  • C
    $y+\sqrt{3} x-5=0$
  • D
    $y-\sqrt{3} x-5=0$

Solution

Slope of the required line, $\mathrm{m}=\tan 120^{\circ}=-\sqrt{3}$ (since it is making angle with positive direction of x -axis). Given, line cuts off an intercept of 5 units on negative direction of $y$-axis. This means line is intersecting $y$ axis at $(0,-5)$

Hence, the correct answer is option: 'A'.

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