Q89 / 160 · AP EAMCET 2023 (18 May Shift 2) · Mathematics
The equation of a plane passing through $(-1,2,3)$ and whose normal makes equal angles with the coordinate axes is
- A$x+y+z+4=0$
- B$x-y+z+4=0$
- Correct answerC$x+y+z-4=0$
- D$x+y+z=0$
Solution
Since, normal makes equal angles with co-ordinate axis. So, it intercept with all the axis will be same. So, equation of plane will be :
$$
\frac{x}{a}+\frac{y}{a}+\frac{z}{a}=1 \Rightarrow x+y+z=a.....(i)
$$
Now, it passes through $(-1,2,3)$. So, we get
$$
-1+2+3=a \Rightarrow a=4
$$
Putting the values of a in equation (i), we get
$$
x+y+z-4=0
$$
Hence, the correct answer is option: 'C'.