Q84 / 160 · AP EAMCET 2021 (25 Aug Shift 2) · Mathematics
The equation of a line though the point (1, 2) whose distance from the point (3, 1) has the greatest value is
- Correct answerAy = 2 x
- By = x + 1
- Cx + 2 y = 5
- Dy = 3x − 1
Solution
We have plotted the diagram based on the given information.
$\begin{aligned} & \because A B \perp C D \\ & \quad \quad m_{A B} \cdot m_{C D}=-1\end{aligned}$

$\begin{aligned} m_{A B} \cdot\left(\frac{1-2}{3-1}\right) & =-1 \\ m_{A B} & =2\end{aligned}$ $\therefore$ Equation of line $A B$ passing through $(1,2)$ is y − 2 = 2(x − 1) $\Rightarrow \quad y=2 x$

$\begin{aligned} m_{A B} \cdot\left(\frac{1-2}{3-1}\right) & =-1 \\ m_{A B} & =2\end{aligned}$ $\therefore$ Equation of line $A B$ passing through $(1,2)$ is y − 2 = 2(x − 1) $\Rightarrow \quad y=2 x$
Hence, the correct answer is option: 'A'.