Q31 / 200 · AP EAMCET 2001 · Chemistry

The energy of an electron present in Bohr's second orbit of hydrogen atom is

  • A
    $-1312 \mathrm{~J}$ atom $^{-1}$
  • Correct answer
    B
    $-328 \mathrm{~kJ} \mathrm{~mol}^{-1}$
  • C
    $-328 \mathrm{~J} \mathrm{~mol}^{-1}$
  • D
    $-164 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Solution

For Bohr's second orbit $\begin{aligned} E_n & =\frac{-1312}{n^2} \mathrm{~kJ} \mathrm{~mol}^{-1}=\frac{-1312}{2^2} \\ & =-328 \mathrm{~kJ} \mathrm{~mol}^{-1}\end{aligned}$

Hence, the correct answer is option: 'B'.

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