Q21 / 60 · NEST (NISER) 2017 · Chemistry

The energy of an electron in the $1 s$ orbital of $\mathrm{H}^{-}, \mathrm{He}, \mathrm{Li}^{+}$and $\mathrm{Be}^{2+}$ follows the order

  • Correct answer
    A
    $\mathrm{H}^{-} \gt \mathrm{He} \gt \mathrm{Li}^{+} \gt \mathrm{Be}^{2+}$
  • B
    $\mathrm{Li}^{+} \gt \mathrm{Be}^{2+} \gt \mathrm{He} \gt \mathrm{H}^{-}$
  • C
    $\mathrm{Be}^{2+} \gt \mathrm{Li}^{+} \gt \mathrm{He} \gt \mathrm{H}^{-}$
  • D
    $\mathrm{H}^{-} \gt \mathrm{Li}^{+} \gt \mathrm{He} \gt \mathrm{Be}^{2+}$

Hence, the correct answer is option: 'A'.

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