Q54 / 200 · NEET 2011 (Screening) · Chemistry

The energies $E_1$ and $E_2$ of two radiations are $25 \mathrm{eV}$ and $50 \mathrm{eV}$ respectively. The relation between their wavelengths i.e., $\lambda_1$ and $\lambda_2$ will be

  • Correct answer
    A
    $\lambda_1=2 \lambda_2$
  • B
    $\lambda_1=4 \lambda_2$
  • C
    $\lambda_1=\frac{1}{2} \lambda_2$
  • D
    $\lambda_1=\lambda_2$

Solution

$$ \begin{aligned} & E_1=25 \mathrm{eV}, E_2=50 \mathrm{eV} \\ & E_1=\frac{h c}{\lambda_1} \text { and } E_2=\frac{h c}{\lambda_2} \\ & \text { or } \frac{E_1}{E_2}=\frac{\lambda_2}{\lambda_1} \end{aligned} $$ or $\frac{25}{50}=\frac{\lambda_2}{\lambda_1}$ or $\lambda_1=2 \lambda_2$

Hence, the correct answer is option: 'A'.

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