The emf of a cell is 6 V and internal resistance is 0.5 kΩ. What will be the reading (in volt) of a voltmeter having an internal resistance of 2.5 kΩ?

Question

MARKS Content Team · Accepted Answer

Correct answer: 5. Total resistance=2.5+0.5=3.0 kΩ=3000 Ω ∴ Current, i=6/3000 A; Reading of voltmeter =i×2.5×1000 =6/3000×2500=5 V

The emf of a cell is $6 V$ and internal resistance is $0.5$ $k Ω$ . What will be the reading (in volt) of a voltmeter having an internal resistance of $2.5$ $k Ω?$

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