Q123 / 160 · JIPMER 2006 · Physics

The element ${ }_{90} \mathrm{Th}^{232}$ belongs to thorium series. Which of the following will act as the end product of the series ?

  • Correct answer
    A
    ${ }_{82} \mathrm{~Pb}^{208}$
  • B
    ${ }_{82} \mathrm{Bi}^{209}$
  • C
    ${ }_{82} \mathrm{~Pb}^{206}$
  • D
    ${ }_{82} \mathrm{~Pb}^{207}$

Solution

The end product of thorium series is $\mathrm{Pb}-208$.

Hence, the correct answer is option: 'A'.

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