Q56 / 180 · AIIMS 2001 · Chemistry

The electronic configuration $1 s^2 2 s^2 2 p^5 3 s^1$ shows

  • A
    ground state of fluorine atom
  • B
    excited state of fluorine atom
  • Correct answer
    C
    excited state of neon atom
  • D
    excited state of ion $\mathrm{O}_2^{-}$

Solution

The ground state electronic configuration of neon atom $(Z=10)$ is : $$ 1 s^2, 2 s^2, 2 p^6 $$ Therefore first excited state of Neon will be : $$ 1 s^2, 2 s^2, 2 p^5, 3 s^1 $$

Hence, the correct answer is option: 'C'.

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