Q39 / 180 · KCET 2007 · Chemistry
The electronic configuration of $\mathrm{Cr}^{3+}$ is
- A$[\mathrm{Ar}] 3 d^{4} 4 s^{2}$
- Correct answerB$[\mathrm{Ar}] 3 d^{3} 4 s^{0}$
- C$[\mathrm{Ar}] 3 d^{2} 4 s^{1}$
- D$[\mathrm{Ar}] 3 d^{5} 4 s^{1}$
Solution
$\mathrm{Cr}(24):[\mathrm{Ar}] 3 d^{5} 4 s^{1}$
$$
\mathrm{Cr}^{3+}:[\mathrm{Ar}] 3 d^{3} 4 s^{0}
$$
Hence, the correct answer is option: 'B'.