Q39 / 180 · KCET 2007 · Chemistry

The electronic configuration of $\mathrm{Cr}^{3+}$ is

  • A
    $[\mathrm{Ar}] 3 d^{4} 4 s^{2}$
  • Correct answer
    B
    $[\mathrm{Ar}] 3 d^{3} 4 s^{0}$
  • C
    $[\mathrm{Ar}] 3 d^{2} 4 s^{1}$
  • D
    $[\mathrm{Ar}] 3 d^{5} 4 s^{1}$

Solution

$\mathrm{Cr}(24):[\mathrm{Ar}] 3 d^{5} 4 s^{1}$ $$ \mathrm{Cr}^{3+}:[\mathrm{Ar}] 3 d^{3} 4 s^{0} $$

Hence, the correct answer is option: 'B'.

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