Q14 / 180 · COMEDK 2020 · Chemistry
The electronic configuration of $\mathrm{Cr}^{3+}$ is
- A[Ar] $3 d^{5} 4 s^{1}$
- B$[\mathrm{Ar}] 3 d^{2} 4 s^{1}$
- Correct answerC$[\mathrm{Ar}] 3 d^{3} 4 s^{0}$
- D$[\mathrm{Ar}] 3 d^{4} 4 s^{2}$
Solution
Electronic configuration of $\mathrm{Cr}=[\mathrm{Ar}] 3 d^{5} 4 s^{1}$
Electronic configuration of $\mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 d^{3} 4 s^{0}$
Hence, the correct answer is option: 'C'.