Q2 / 90 · KVPY 2015 (SB/SX) · Chemistry
The electronic configuration of an element with the largest difference between the $1^{\text {st }}$ and $2^{\text {nd }}$ ionization energies is
- A$1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}$
- Correct answerB$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
- C$1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6} 3 \mathrm{~s}^{2}$
- D$1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{1}$
Hence, the correct answer is option: 'B'.