Q10 / 90 · JEE Main 2024 (06 Apr Shift 1) · Chemistry

The electron affinity value are negative for A. \(\mathrm{Be} \rightarrow \mathrm{Be}^{-}\) B. \(\mathrm{N} \rightarrow \mathrm{N}^{-}\) C. \(\mathrm{O} \rightarrow \mathrm{O}^{2-}\) D. \(\mathrm{Na} \rightarrow \mathrm{Na}^{-}\) E. \(\mathrm{Al} \rightarrow \mathrm{Al}^{-}\) Choose the most appropriate answer from the options given below :

  • A
    D and E only
  • Correct answer
    B
    A, B and C only
  • C
    A and D only
  • D
    A, B, D and E only

Solution

(A) $\mathrm{Be}+\mathrm{e}^{-} \rightarrow \mathrm{Be}^{-}, \quad$ E.A $=-$ ive (B) $\mathrm{N}+\mathrm{e}^{-} \rightarrow \mathrm{N}^{-} \quad$ E.A $=$-ive (C) $\mathrm{O}+\mathrm{e}^{-} \rightarrow \mathrm{O}^{-}$ $\mathrm{O}^{-}+\mathrm{e}^{-} \rightarrow \mathrm{O}^{-2} \quad$ E.A $=-$ ive (D) $\mathrm{Na}+\mathrm{e}^{-} \rightarrow \mathrm{Na}^{-} \quad$ E.A $=+$ ive (E) $\mathrm{A} \ell+\mathrm{e}^{-} \rightarrow \mathrm{A} \ell^{-} \quad$ E.A $=+$ ive

Hence, the correct answer is option: 'B'.

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