The electrode reaction that takes place at the anode of $\mathrm{CH}_{4}-\mathrm{O}_{2}$ fuel cell is

• A

  $2 \mathrm{O}_{2}+8 \mathrm{H}^{+}+8 \mathrm{e}^{-} \rightarrow 4 \mathrm{H}_{2} \mathrm{O}$
• Correct answer
  B

  $\mathrm{CH}_{4}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{CO}_{2}+8 \mathrm{H}^{+}+8 \mathrm{e}^{-}$
• C

  $\mathrm{CH}_{4}+2 \mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O}$
• D

  $2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2}$

Hence, the correct answer is option: 'B'.