Q78 / 120 · VITEEE 2013 · Mathematics
The domain of the function
$f(x)=\frac{1}{\log _{10}(1-x)}+\sqrt{x+2}$ is
- A$]-3,-2.5[\cap]-2.5,-2[$
- Correct answerB$[-2,0[\cup] 0,1]$
- C$] 0,1[$
- DNone of the above
Solution
$x+2 \geq 0$, i.e., $x \geq-2$ or $-2 \leq x$ $\log _{10}(1-x) \neq 0$ $\Rightarrow 1-x \neq 1 \Rightarrow x \neq 0$ Again, $1-x>0$ $\Rightarrow 1>x \Rightarrow x < 1$
Combining all the results for values of $x$, we get
$-2 \leq x < 0 \text { and } 0 < x < 1$
Hence, the correct answer is option: 'B'.