Q86 / 155 · WBJEE 2020 · Mathematics

The domain of $f(x)=\sqrt{\left(\frac{1}{\sqrt{x}}-\sqrt{x+1}\right)}$ is

  • A
    $x>-1$
  • B
    $(-1, \infty)$ K $\{0\}$
  • Correct answer
    C
    $\left(0, \frac{\sqrt{5}-1}{2}\right]$
  • D
    $\left[\frac{1-\sqrt{5}}{2}, 0\right)$

Solution

Hint: $x^{2}+x \leq 1$ and $x>0$ $x \in\left[\frac{-1-\sqrt{5}}{2}, \frac{\sqrt{5}-1}{2}\right]$ $x \in\left(0, \frac{\sqrt{5}-1}{2}\right]$

Hence, the correct answer is option: 'C'.

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