Q91 / 160 · AP EAMCET 2020 (07 Oct Special) · Mathematics
The distance between the parallel lines $9 x^2-6 x y+y^2+18 x-6 y+8=0$ is
- A$\sqrt{10}$
- B2
- C$\frac{2 \sqrt{153}}{\sqrt{10}}$
- Correct answerD$\frac{2}{\sqrt{10}}$
Hence, the correct answer is option: 'D'.