Q1 / 104 · NTA Abhyas (NEET) 2020 · Chemistry · p Block Elements (Group 13 & 14)

The dissolution of Al(OH)3 by a solution of NaOH results in the formation of:

  • A
    [Al(H2O)4(OH)2]+
  • B
    [Al(H2O)3(OH)3]
  • Correct answer
    C
    [Al(H2O)2(OH)4]-
  • D
    [Al(H2O)6(OH)3]

Solution

Al(OH)3+NaOH(solution)→[Al(H2O)2(OH)4]Θ or NaAlO2 .

Hence, the correct answer is option: 'C'.

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