Q126 / 180 · AIIMS 2018 (27 May) · Physics
The displacement-time graphs of two moving particles make angles of $30^{\circ}$ and $45^{\circ}$ with the time axis. The ratio of their velocities is


- A$\sqrt{3}: 2$
- B$1: 1$
- C$1: 2$
- Correct answerD$1: \sqrt{3}$
Solution
Slope of displacement-time graph gives velocity.

$\begin{aligned} \therefore \frac{v_1}{v_2} & =\frac{\tan \theta_1}{\tan \theta_2} \\ & =\frac{\tan 30^{\circ}}{\tan 45^{\circ}}=\frac{1}{\sqrt{3}}\end{aligned}$

$\begin{aligned} \therefore \frac{v_1}{v_2} & =\frac{\tan \theta_1}{\tan \theta_2} \\ & =\frac{\tan 30^{\circ}}{\tan 45^{\circ}}=\frac{1}{\sqrt{3}}\end{aligned}$
Hence, the correct answer is option: 'D'.